

If all circles have area $10$, then at most $3659$ circles can fit in that area. The Rectangular disc packing array (with zero spacing) is 78.5 (does not suffer from the low efficiency of edge effects) The Hexagonal disc packing array (with zero spacing) is 90.6 Worst case disc packing is (2 discs inside a square) 53.

If the rectangle is $257 \times 157$ and the radius of a circle is $\sqrt \approx 36592.5$. The efficiency of disc packing depends on the arrangement of discs in the material. (Also, if the rectangle is only $2m \cdot r$ units tall, we can alternate columns with $m$ and $m-1$ circles.) However, 3 circles do have space in that with the following setup: Again, this does not really answer the general case, but shows that even in small cases the hexagonal packing may not find the optimum.
PACK CIRCLES IN RECTANGLE FREE
Free for commercial use High Quality Images. Choosing b 1.6 and l 2.6 won't allow any of those setups to fit in more than 2 circles.
PACK CIRCLES IN RECTANGLE DOWNLOAD
So if you want the triangular packing to have $m$ circles in each column, and $n$ columns, then the rectangle must be at least $(2m+1) \cdot r$ units tall and $(2 + (n-1)\sqrt3) \cdot r$ units long. Find & Download Free Graphic Resources for Circles Rectangle. Each pair of vertical blue lines is a distance $r \sqrt 3$ apart, and they're still a distance $r$ from the edges. If the circles have radius $r$, then each pair of horizontal red lines is a distance $r$ apart, and they're a distance $r$ from the edges. If you want to fill the rectangle more systematically and completely, youll have to use the Euclidean Distance Transform to figure out the size of the largest. Giving the profit of each circle is: P(a) = 200 - 200/a (a is the area of the circle)Ĭonsider the following diagram of a triangular packing: So my question is: Did I calculate it in a correct way? Are there any other more effective calculation methods?īecause in later question, it asks me to find the area of the circle to so that we get the maximum profit. However, I find my math calculation kinda inefficient, long, and not correct in any other cases. > That means in this case, i can fit in 43*72= 3096 circlesĢ) Then I try triangular pattern, which can fit more circles, 3575 circles.
